RBI Assistant Prelims Test Series 5, RBI Assistant Prelims Mock Test
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RBI Assistant Prelims Test Series 5, RBI Assistant Prelims Mock Test Series 5. RBI Exam Online Test 2025, RBI Assistant Pre Free Mock Test Exam 2025. RBI Assistant exam is conducted by RBI to recruit candidates for the Assistant to its various branches all over the country. As it is a national level recruitment process, applications from all sections of India are invited. RBI Assistant Pre. Question and Answers in English and Hindi Series 5. Here we are providing RBI Assistant Pre. Full Mock Test Paper in English. RBI Assistant Pre. Mock Test Series 5th 2025. Now Test your self for RBI Assistant Pre. Exam by using below quiz…
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Question 1 of 50
1. Question
A 25 cm wide path is to be made around a circular garden having a diameter of 4 meters. Approximate area of the path is square meters is
Correct
Area of the path = Area of the outer circle – Area of the inner circle = ∏{4/2 + 25/100}2 – ∏[4/2]2
= ∏[2.252 – 22] = ∏(0.25)(4.25) { (a2 – b2 = (a – b)(a + b) }
= (3.14)(1/4)(17/4) = 53.38/16 = 3.34 sq mIncorrect
Area of the path = Area of the outer circle – Area of the inner circle = ∏{4/2 + 25/100}2 – ∏[4/2]2
= ∏[2.252 – 22] = ∏(0.25)(4.25) { (a2 – b2 = (a – b)(a + b) }
= (3.14)(1/4)(17/4) = 53.38/16 = 3.34 sq m -
Question 2 of 50
2. Question
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either blue or yellow?
Correct
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. Probability that both marbles are blue = ³C₂/¹⁵C₂ = (3 * 2)/(15 * 14) = 1/35
Probability that both are yellow = ²C₂/¹⁵C₂ = (2 * 1)/(15 * 14) = 1/105
Probability that one blue and other is yellow = (³C₁ * ²C₁)/¹⁵C₂ = (2 * 3 * 2)/(15 * 14) = 2/35
Required probability = 1/35 + 1/105 + 2/35
= 3/35 + 1/105 = 1/35(3 + 1/3)
= 10/(3 * 35) = 2/21Incorrect
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. Probability that both marbles are blue = ³C₂/¹⁵C₂ = (3 * 2)/(15 * 14) = 1/35
Probability that both are yellow = ²C₂/¹⁵C₂ = (2 * 1)/(15 * 14) = 1/105
Probability that one blue and other is yellow = (³C₁ * ²C₁)/¹⁵C₂ = (2 * 3 * 2)/(15 * 14) = 2/35
Required probability = 1/35 + 1/105 + 2/35
= 3/35 + 1/105 = 1/35(3 + 1/3)
= 10/(3 * 35) = 2/21 -
Question 3 of 50
3. Question
Rajan got married 8 years ago. His present age is 6/5 times his age at the time of his marriage. Rajan’s sister was 10 years younger to him at the time of his marriage. The age of Rajan’s sister is:
Correct
Let Rajan’s present age be x years.
Then, his age at the time of marriage = (x – 8) years.
x = 6/5 (x – 8)
5x = 6x – 48 => x = 48
Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = 30 years.
Rajan’s sister’s present age = (30 + 8) = 38 years.Incorrect
Let Rajan’s present age be x years.
Then, his age at the time of marriage = (x – 8) years.
x = 6/5 (x – 8)
5x = 6x – 48 => x = 48
Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = 30 years.
Rajan’s sister’s present age = (30 + 8) = 38 years. -
Question 4 of 50
4. Question
Rs. 800 becomes Rs. 956 in 3 years at a rate of S.I. If the rate of interest is increased by 4%, what amount will Rs. 800 become in 3 years?
Correct
S.I. = (956 – 800) = Rs. 156.
Rate = (100 * 156) / (800 * 3) = 6 1/2 %
Now rate = (6 1/2 + 4) = 10 1/2 %
New S.I. = (800 * 21/2 * 3/100) = Rs. 252
New amount = (800 + 252) = Rs. 1052.Incorrect
S.I. = (956 – 800) = Rs. 156.
Rate = (100 * 156) / (800 * 3) = 6 1/2 %
Now rate = (6 1/2 + 4) = 10 1/2 %
New S.I. = (800 * 21/2 * 3/100) = Rs. 252
New amount = (800 + 252) = Rs. 1052. -
Question 5 of 50
5. Question
A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work?
Correct
HCF of 1189, 1073 = 29
1073/29 = 37Incorrect
HCF of 1189, 1073 = 29
1073/29 = 37 -
Question 6 of 50
6. Question
The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is?
Correct
S = 1
M = x
DS = x + 1
US = x – 1
35/(x + 1) + 35/(x – 1) = 12
x = 6Incorrect
S = 1
M = x
DS = x + 1
US = x – 1
35/(x + 1) + 35/(x – 1) = 12
x = 6 -
Question 7 of 50
7. Question
The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is:
Correct
Speed = [90 * 5/18] m/sec = 25 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 25 → x = 25 * 60 / 2 = 750Incorrect
Speed = [90 * 5/18] m/sec = 25 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 25 → x = 25 * 60 / 2 = 750 -
Question 8 of 50
8. Question
An engineering student has to secure 36% marks to pass. He gets 130 marks and fails by 14 marks. The maximum No. of marks obtained by him is?
Correct
130
14
——-
361—— 144
100%——? => 400Incorrect
130
14
——-
361—— 144
100%——? => 400 -
Question 9 of 50
9. Question
Two-third of a positive number and 25/216 of its reciprocal are equal. The number is:
Correct
Let the number be x. Then,
2/3 x = 25/216 * 1/x
x2 = 25/216 * 3/2 = 25/144
x = 5/12Incorrect
Let the number be x. Then,
2/3 x = 25/216 * 1/x
x2 = 25/216 * 3/2 = 25/144
x = 5/12 -
Question 10 of 50
10. Question
The average of first 10 natural numbers is?
Correct
Sum of 10 natural no. = 110/2 = 55
Average = 55/10 = 5.5Incorrect
Sum of 10 natural no. = 110/2 = 55
Average = 55/10 = 5.5 -
Question 11 of 50
11. Question
A can do a piece of work in 4 days. B can do it in 5 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?
Correct
C = 1/2 – 1/4 – 1/5 = 1/20 => 20 days
Incorrect
C = 1/2 – 1/4 – 1/5 = 1/20 => 20 days
-
Question 12 of 50
12. Question
Twelve men and six women together can complete a piece of work in four days. The work done by a women in one day is half the work done by a man in one day. If 12 men and six women started working and after two days, six men left and six women joined, then in hoe many more days will the work be completed?
Correct
Work done by a women in one day = 1/2 (work done by a man/day)
One women’s capacity = 1/2(one man’s capacity)
One man = 2 women.
12 men = 24 women.
12 men + 6 women = 30 women
30 women can complete the work in four days. In the first 2 days they can complete 1/2 of the work. Remaining part of the work = 1/2. If 6 men leave and 6 new women join, then new work force = 30 women – 12 women + 6 women = 24 women.
Time taken by them to complete the remaining work = 1/2 (Time taken by 24 women to complete the work) = 1/2 * (30 * 4)/24 = 2 (1/2) days.Incorrect
Work done by a women in one day = 1/2 (work done by a man/day)
One women’s capacity = 1/2(one man’s capacity)
One man = 2 women.
12 men = 24 women.
12 men + 6 women = 30 women
30 women can complete the work in four days. In the first 2 days they can complete 1/2 of the work. Remaining part of the work = 1/2. If 6 men leave and 6 new women join, then new work force = 30 women – 12 women + 6 women = 24 women.
Time taken by them to complete the remaining work = 1/2 (Time taken by 24 women to complete the work) = 1/2 * (30 * 4)/24 = 2 (1/2) days. -
Question 13 of 50
13. Question
A wholesale tea dealer 408 kilograms, 468 kilograms and 516 kilograms of three different qualities of tea. He wants it all to be packed into boxes of equal size without mixing. Find the capacity of the largest possible box?
Correct
HCF of 408, 468, 516 = 12
Incorrect
HCF of 408, 468, 516 = 12
-
Question 14 of 50
14. Question
Find the one which does not belong to that group ?
Correct
27, 36, 72 and 45 are divisible by 9, but not 30.
Incorrect
27, 36, 72 and 45 are divisible by 9, but not 30.
-
Question 15 of 50
15. Question
How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction?
Correct
The distance to be covered = Sum of their lengths = 200 + 300 = 500 m.
Relative speed = 72 -36 = 36 kmph = 36 * 5/18 = 10 mps.
Time required = d/s = 500/10 = 50 sec.Incorrect
The distance to be covered = Sum of their lengths = 200 + 300 = 500 m.
Relative speed = 72 -36 = 36 kmph = 36 * 5/18 = 10 mps.
Time required = d/s = 500/10 = 50 sec. -
Question 16 of 50
16. Question
A sum of Rs. 125000 amounts to Rs. 15500 in 4 years at the rate of simple interest. What is the rate of interest?
Correct
S.I. = (15500 – 12500) = Rs. 3000\
Rate = (100 * 3000) / (12500 * 4) = 6%Incorrect
S.I. = (15500 – 12500) = Rs. 3000\
Rate = (100 * 3000) / (12500 * 4) = 6% -
Question 17 of 50
17. Question
217 * 217 + 183 * 183 = ?
Correct
(217)2 + (183)2 = (200 + 17)2 + (200 – 17)2
= 2[(200)2 + (17)2] = 2(40000 + 289) = 80578Incorrect
(217)2 + (183)2 = (200 + 17)2 + (200 – 17)2
= 2[(200)2 + (17)2] = 2(40000 + 289) = 80578 -
Question 18 of 50
18. Question
Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran’s share in the profit?
Correct
Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran’s share = 24500 * 3/7 = Rs. 10500Incorrect
Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran’s share = 24500 * 3/7 = Rs. 10500 -
Question 19 of 50
19. Question
Which one of the following numbers is exactly divisible by 11?
Correct
(4 + 5 + 2) – (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) – (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) – (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) – (2 + 5 + 4) = 0.
So, 415624 is divisible by 11.Incorrect
(4 + 5 + 2) – (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) – (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) – (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) – (2 + 5 + 4) = 0.
So, 415624 is divisible by 11. -
Question 20 of 50
20. Question
The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?
Correct
2(3x + x) = 96
l = 36 b = 12
lb = 36 * 12 = 432Incorrect
2(3x + x) = 96
l = 36 b = 12
lb = 36 * 12 = 432 -
Question 21 of 50
21. Question
Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 496.80?
Correct
CP = Rs. 540, MP = 540 + 15% of 540 = Rs. 621
SP = Rs. 496.80, Discount = 621 – 496.80 = 124.20
Discount % = 124.2/621 * 100 = 20%Incorrect
CP = Rs. 540, MP = 540 + 15% of 540 = Rs. 621
SP = Rs. 496.80, Discount = 621 – 496.80 = 124.20
Discount % = 124.2/621 * 100 = 20% -
Question 22 of 50
22. Question
A tradesman by means of his false balance defrauds to the extent of 20%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
Correct
g% = 20 + 20 + (20*20)/100
= 44%Incorrect
g% = 20 + 20 + (20*20)/100
= 44% -
Question 23 of 50
23. Question
A and B start a business, with A investing the total capital of Rs.50000, on the condition that B pays A interest @ 10% per annum on his half of the capital. A is a working partner and receives Rs.1500 per month from the total profit and any profit remaining is equally shared by both of them. At the end of the year, it was found that the income of A is twice that of B. Find the total profit for the year?
Correct
Interest received by A from B = 10% of half of Rs.50000 = 10% * 25000 = 2500.
Amount received by A per annum for being a working partner = 1500 * 12 = Rs.18000.
Let ‘P’ be the part of the remaining profit that A receives as his share. Total income of A = (2500 + 18000 + P)
Total income of B = only his share from the remaining profit = ‘P’, as A and B share the remaining profit equally.
Income of A = Twice the income of B
(2500 + 18000 + P) = 2(P)
P = 20500
Total profit = 2P + 18000
= 2*20500 + 18000 = 59000Incorrect
Interest received by A from B = 10% of half of Rs.50000 = 10% * 25000 = 2500.
Amount received by A per annum for being a working partner = 1500 * 12 = Rs.18000.
Let ‘P’ be the part of the remaining profit that A receives as his share. Total income of A = (2500 + 18000 + P)
Total income of B = only his share from the remaining profit = ‘P’, as A and B share the remaining profit equally.
Income of A = Twice the income of B
(2500 + 18000 + P) = 2(P)
P = 20500
Total profit = 2P + 18000
= 2*20500 + 18000 = 59000 -
Question 24 of 50
24. Question
In how much time would the simple interest on a certain sum be 0.125 times the principal at 10% per annum?
Correct
Let sum = x. Then, S.I. = 0.125x = 1/8 x, R = 10%
Time = (100 * x) / (x * 8 * 10) = 5/4 = 1 1/4 years.Incorrect
Let sum = x. Then, S.I. = 0.125x = 1/8 x, R = 10%
Time = (100 * x) / (x * 8 * 10) = 5/4 = 1 1/4 years. -
Question 25 of 50
25. Question
If x = √8 – √7, y = √6 – √5 and z = √10 – 3, which of the following is true?
Correct
x = √8 – √7 = 1/(√8 + √7) and y = √6 – √5 = 1/(√6 + √5) and z = √10 – 3 = 1/(√10 + 3)
As (√8 + √7) > (√6 + √5), (√8 – √7) < (√6 - √5) As (√10 + 3) > (√8 + √7) > (√6 + √5)
z < x < y.Incorrect
x = √8 – √7 = 1/(√8 + √7) and y = √6 – √5 = 1/(√6 + √5) and z = √10 – 3 = 1/(√10 + 3)
As (√8 + √7) > (√6 + √5), (√8 – √7) < (√6 - √5) As (√10 + 3) > (√8 + √7) > (√6 + √5)
z < x < y. -
Question 26 of 50
26. Question
What is the difference between the largest and the smallest number written with 7, 7, 0, 7?
Correct
7770
7077
————-
693Incorrect
7770
7077
————-
693 -
Question 27 of 50
27. Question
Find the one which does not belong to that group ?
Correct
8 = 23, 27 = 33, 64 = 43, 125 = 53 and 343 = 73.
8, 27, 125 and 343 are cubes of prime numbers but not 64.Incorrect
8 = 23, 27 = 33, 64 = 43, 125 = 53 and 343 = 73.
8, 27, 125 and 343 are cubes of prime numbers but not 64. -
Question 28 of 50
28. Question
Find the smallest number which should be multiplied with 520 to make it a perfect square.
Correct
520 = 26 * 20 = 2 * 13 * 22 * 5 = 23 * 13 * 5
Required smallest number = 2 * 13 * 5 = 130
130 is the smallest number which should be multiplied with 520 to make it a perfect square.Incorrect
520 = 26 * 20 = 2 * 13 * 22 * 5 = 23 * 13 * 5
Required smallest number = 2 * 13 * 5 = 130
130 is the smallest number which should be multiplied with 520 to make it a perfect square. -
Question 29 of 50
29. Question
Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 km more than the second. The distance between P and Q is?
Correct
At the time of meeting, let the distance traveled by the second train be x km. Then, distance covered by the first train is (x + 100) km.
x/40 = (x + 100)/50
50x = 40x + 4000 => x = 400
So, distance between P and Q = (x + x + 100)km = 900 km.Incorrect
At the time of meeting, let the distance traveled by the second train be x km. Then, distance covered by the first train is (x + 100) km.
x/40 = (x + 100)/50
50x = 40x + 4000 => x = 400
So, distance between P and Q = (x + x + 100)km = 900 km. -
Question 30 of 50
30. Question
Find the one which does not belong to that group ?
Correct
G-1F+3I, Q-2O+3R, L-1K+3N, Y-1X+3A and T-1S+3V.
Except QOR, all other groups follows similar pattern.Incorrect
G-1F+3I, Q-2O+3R, L-1K+3N, Y-1X+3A and T-1S+3V.
Except QOR, all other groups follows similar pattern. -
Question 31 of 50
31. Question
By selling 150 mangoes, a fruit-seller gains the selling price of 30 mangoes. Find the gain percent?
Correct
SP = CP + g
150 SP = 150 CP + 30 SP
120 SP = 150 CP
120 — 30 CP
100 — ? => 25%Incorrect
SP = CP + g
150 SP = 150 CP + 30 SP
120 SP = 150 CP
120 — 30 CP
100 — ? => 25% -
Question 32 of 50
32. Question
A sum amount to Rs.1344 in two years at simple interest. What will be the compound interest on the same sum at the same rate of interest for the same period?
Correct
Incorrect
-
Question 33 of 50
33. Question
The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?
Correct
2C + 3T = 1300 — (1)
3C + 3T = 1200 — (2)
Subtracting 2nd from 1st, we get
-C + T = 100 => T – C = 100Incorrect
2C + 3T = 1300 — (1)
3C + 3T = 1200 — (2)
Subtracting 2nd from 1st, we get
-C + T = 100 => T – C = 100 -
Question 34 of 50
34. Question
P alone can complete a piece of work in 6 days. Work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?
Correct
Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.
Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total
They would take 9/2 days = 4 (1/2) days to complete the work working together.Incorrect
Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.
Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total
They would take 9/2 days = 4 (1/2) days to complete the work working together. -
Question 35 of 50
35. Question
A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group?
Correct
Two men, three women and one child can be selected in ⁴C₂ * ⁶C₃ * ⁵C₁ ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 5
= 600 ways.Incorrect
Two men, three women and one child can be selected in ⁴C₂ * ⁶C₃ * ⁵C₁ ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 5
= 600 ways. -
Question 36 of 50
36. Question
The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?
Correct
400*(90/100)*(95/100) = 342
Incorrect
400*(90/100)*(95/100) = 342
-
Question 37 of 50
37. Question
A certain number successively divided by 2, 5 and 7 leaves remainders 1, 2 and 3 respectively. When the same number is divided by 70, what is the remainder?
Correct
2) 105 (52 5) 52 (10 7) 10 (1
104 50 7
——– ——– – —–
1 2 3
=> 65
105/70 = 35 (Remainder)Incorrect
2) 105 (52 5) 52 (10 7) 10 (1
104 50 7
——– ——– – —–
1 2 3
=> 65
105/70 = 35 (Remainder) -
Question 38 of 50
38. Question
A man sells a horse for Rs.800 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse?
Correct
CP = SP + 1CP = SP – g
800 + x = 980 – 2x
3x = 180 => x = 60
CP = 800 + 60 = 860Incorrect
CP = SP + 1CP = SP – g
800 + x = 980 – 2x
3x = 180 => x = 60
CP = 800 + 60 = 860 -
Question 39 of 50
39. Question
666 / 6 / 3 = ?
Correct
Given Exp. = 666 * 1/6 * 1/3 = 37
Incorrect
Given Exp. = 666 * 1/6 * 1/3 = 37
-
Question 40 of 50
40. Question
A rectangular field has area equal to 150 sq m and perimeter 50 m. Its length and breadth must be?
Correct
lb = 150
2(l + b) = 50 => l + b = 25
l – b = 5
l = 15 b = 10Incorrect
lb = 150
2(l + b) = 50 => l + b = 25
l – b = 5
l = 15 b = 10 -
Question 41 of 50
41. Question
Ten years ago, the age of Anand was one-third the age of Bala at that time. The present age of Bala is 12 years more than the present age of Anand. Find the present age of Anand?
Correct
Let the present ages of Anand and Bala be ‘a’ and ‘b’ respectively.
a – 10 = 1/3 (b – 10) — (1)
b = a + 12
Substituting b = a + 12 in first equation,
a – 10 = 1/3 (a + 2) => 3a – 30 = a + 2
=> 2a = 32 => a = 16.Incorrect
Let the present ages of Anand and Bala be ‘a’ and ‘b’ respectively.
a – 10 = 1/3 (b – 10) — (1)
b = a + 12
Substituting b = a + 12 in first equation,
a – 10 = 1/3 (a + 2) => 3a – 30 = a + 2
=> 2a = 32 => a = 16. -
Question 42 of 50
42. Question
Two pipes A and B can separately fill a tank in 2 minutes and 15 minutes respectively. Both the pipes are opened together but 4 minutes after the start the pipe A is turned off. How much time will it take to fill the tank?
Correct
4/12 + x/15 = 1
x = 10Incorrect
4/12 + x/15 = 1
x = 10 -
Question 43 of 50
43. Question
2 1/3 + 4 1/6 – 2 2/3 – 1 1/2 = 2 ?/3
Correct
2 1/3 + 4 1/6 – 2 2/3 – 1 1/2 = 2 ?/3
= 7/3 + 25/6 – 8/3 – 3/2 = (14 + 25 – 16 – 9)/6 = 7/3 = 2 1/3
? = 1Incorrect
2 1/3 + 4 1/6 – 2 2/3 – 1 1/2 = 2 ?/3
= 7/3 + 25/6 – 8/3 – 3/2 = (14 + 25 – 16 – 9)/6 = 7/3 = 2 1/3
? = 1 -
Question 44 of 50
44. Question
A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
Correct
Relative speed of the thief and policeman = 11 – 10 = 1 km/hr.
Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.
Distance between the thief and policeman = 200 – 100 = 100 m.Incorrect
Relative speed of the thief and policeman = 11 – 10 = 1 km/hr.
Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.
Distance between the thief and policeman = 200 – 100 = 100 m. -
Question 45 of 50
45. Question
The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is?
Correct
LCM = 1400
1400 – 6 = 1394Incorrect
LCM = 1400
1400 – 6 = 1394 -
Question 46 of 50
46. Question
The sum of the present ages of father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be:
Correct
Let the present ages of son and father be x and (60 – x) years respectively.
Then, (60 – x) – 6 = 5(x – 6)
6x = 84 => x = 14
Son’s age after 6 years = (x + 6) = 20 years.Incorrect
Let the present ages of son and father be x and (60 – x) years respectively.
Then, (60 – x) – 6 = 5(x – 6)
6x = 84 => x = 14
Son’s age after 6 years = (x + 6) = 20 years. -
Question 47 of 50
47. Question
Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
Correct
Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5 = 10.8 sec.Incorrect
Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5 = 10.8 sec. -
Question 48 of 50
48. Question
Three seventh of a number is 12 more than 40% of that number. What will be the 60% of that number?
Correct
3/7 x – 40/100 x = 12
x = 35 * 12
35 * 12 * 60/100 = 252/2 = 126Incorrect
3/7 x – 40/100 x = 12
x = 35 * 12
35 * 12 * 60/100 = 252/2 = 126 -
Question 49 of 50
49. Question
A can do a job in 18 days and B can do it in 30 days. A and B working together will finish twice the amount of work in ——- days?
Correct
1/18 + 1/30 = 8/90 = 4/45
45/4 = 11 ¼ *2 = 22 ½ daysIncorrect
1/18 + 1/30 = 8/90 = 4/45
45/4 = 11 ¼ *2 = 22 ½ days -
Question 50 of 50
50. Question
The least number of four digits which is divisible by 4, 6, 8 and 10 is?
Correct
LCM = 120
120) 1000 (8
960
——-
40
1000 + 120 – 40 = 1080Incorrect
LCM = 120
120) 1000 (8
960
——-
40
1000 + 120 – 40 = 1080