RBI Assistant Online Test, RBI Assistant Prelims Online Test Series 4th
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RBI Assistant Online Test, RBI Assistant Prelims Online Test Series 4th. RBI Exam Online Test 2025, RBI Assistant Pre Free Mock Test Exam 2025. RBI Assistant Pre. Exam Free Online Quiz 2025, RBI Assistant Pre.ย Full Online Mock Test Series 4thย in English.Theย RBI Assistant Exam patternย is same as otherย bank clerkย exams followed by Preliminary, Main and Language Proficiency Test. Last year new changes were introduced in the exam pattern. RBI Assistant Pre Question and Answers in English and Hindiย Series 4. Here we are providingย RBI Assistant Pre.ย Full Mock Test Paper in English. RBI Assistant Pre.ย Mock Test Series 4thย 2025. Now Test your self for RBI Assistant Pre.ย Exam by using below quizโฆ
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Question 1 of 50
1. Question
Find the lowest common multiple of 24, 36 and 40.
Correct
2 24 – 36 – 40
——————–
2 12 – 18 – 20
——————–
2 6 – 9 – 10
——————-
3 3 – 9 – 5
——————–
1 – 3 – 5
L.C.M = 2 * 2 * 2 * 3 * 3 * 5 = 360.Incorrect
2 24 – 36 – 40
——————–
2 12 – 18 – 20
——————–
2 6 – 9 – 10
——————-
3 3 – 9 – 5
——————–
1 – 3 – 5
L.C.M = 2 * 2 * 2 * 3 * 3 * 5 = 360. -
Question 2 of 50
2. Question
Three persons A, B and C divide a certain amount of money such that A’s share is Rs. 4 less than half of the total amount, B’s share is Rs. 8 more than half of what is left and finally C takes the rest which is Rs. 14. Find the total amount they initially had with them?
Correct
Let the total amount be Rs. p.
Let shares of A and B be Rs. x and Rs. y respectively.
C’s share was Rs. 14
we have, x + y + 14 = p —– (1)
From the given data, x = (p/2) – 4 —– (2)
Remaining amount = p – (p/2 – 4) => p/2 + 4.
y = 1/2(p/2 + 4) + 8 => p/4 + 10 —– (3)
From (1), (2) and (3)
p/2 – 4 + p/4 + 10 + 14 = p
3p/4 + 20 = p
p/4 = 20 => p = Rs. 80.Incorrect
Let the total amount be Rs. p.
Let shares of A and B be Rs. x and Rs. y respectively.
C’s share was Rs. 14
we have, x + y + 14 = p —– (1)
From the given data, x = (p/2) – 4 —– (2)
Remaining amount = p – (p/2 – 4) => p/2 + 4.
y = 1/2(p/2 + 4) + 8 => p/4 + 10 —– (3)
From (1), (2) and (3)
p/2 – 4 + p/4 + 10 + 14 = p
3p/4 + 20 = p
p/4 = 20 => p = Rs. 80. -
Question 3 of 50
3. Question
A is a working partner and B is a sleeping partner in the business. A puts in Rs.15000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?
Correct
15:25 => 3:5
9600*10/100 = 960
9600 – 960 = 8640
8640*3/8 = 3240 + 960
= 4200Incorrect
15:25 => 3:5
9600*10/100 = 960
9600 – 960 = 8640
8640*3/8 = 3240 + 960
= 4200 -
Question 4 of 50
4. Question
A person travels equal distances with speeds of 3 km/hr, 4 km/hr and 5 km/hr and takes a total time of 47 minutes. The total distance is?
Correct
Let the total distance be 3x km.
Then, x/3 + x/4 + x/5 = 47/60
47x/60 = 47/60 => x = 1.
Total distance = 3 * 1 = 3 km.Incorrect
Let the total distance be 3x km.
Then, x/3 + x/4 + x/5 = 47/60
47x/60 = 47/60 => x = 1.
Total distance = 3 * 1 = 3 km. -
Question 5 of 50
5. Question
A man gains 20% by selling an article for a certain price. If the sells it at double the price, the percentage of profit will be:
Correct
Let C.P. = Rs. x.
Then, S.P. = Rs. (12% of x) = Rs. 6x/5
New S.P. = 2 * 6x/5 = Rs. 12x/5
Profit = 12x/5 – x = Rs. 7x/5
Profit = 7x/5 * 1/x * 100 = 140%.Incorrect
Let C.P. = Rs. x.
Then, S.P. = Rs. (12% of x) = Rs. 6x/5
New S.P. = 2 * 6x/5 = Rs. 12x/5
Profit = 12x/5 – x = Rs. 7x/5
Profit = 7x/5 * 1/x * 100 = 140%. -
Question 6 of 50
6. Question
Sreedhar and Sravan together can do a work in 25 days. With the help of Pavan, they completed the work in 8 days and earned Rs. 225. What is the share of Sravan, if Sreedhar alone can do the work in 75 days?
Correct
Sravan’s one day’s work = 1/25 – 1/75 = 2/75
Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75
Sravan completed 16/75th of total work.
So, his share is 16/75 * 225 = Rs. 48.Incorrect
Sravan’s one day’s work = 1/25 – 1/75 = 2/75
Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75
Sravan completed 16/75th of total work.
So, his share is 16/75 * 225 = Rs. 48. -
Question 7 of 50
7. Question
Product of two co-prime numbers is 117. Their L.C.M should be:
Correct
H.C.F of co-prime numbers is 1.
So, L.C.M = 117/1 = 117.Incorrect
H.C.F of co-prime numbers is 1.
So, L.C.M = 117/1 = 117. -
Question 8 of 50
8. Question
If cost of sugar increases by 25%. How much percent consumption of sugar should be decreased in order to keep expenditure fixed?
Correct
100
125
—–
125 —– 25
100 —— ? => 20%Incorrect
100
125
—–
125 —– 25
100 —— ? => 20% -
Question 9 of 50
9. Question
What is the area of square field whose side of length 15 m?
Correct
15 * 15 = 225 sq m
Incorrect
15 * 15 = 225 sq m
-
Question 10 of 50
10. Question
Two men Amar and Bhuvan have the ratio of their monthly incomes as 6 : 5. The ratio of their monthly expenditures is 3 : 2. If Bhuvan saves one-fourth of his income, find the ratio of their monthly savings?
Correct
Let the monthly incomes of Amar and Bhuvan be 6x and 5x respectively.
Let the monthly expenditure of Amar and Bhuvan be 3y and 2y respectively.
Savings of Bhuvan every month = 1/4(5x)
= (His income) – (His expenditure) = 5x – 2y.
=> 5x = 20x – 8y => y = 15x/8.
Ratio of savings of Amar and Bhuvan
= 6x – 3y : 1/4(5x) = 6x – 3(15x/8) : 5x/4 = 3x/8 : 5x/4
= 3 : 10.Incorrect
Let the monthly incomes of Amar and Bhuvan be 6x and 5x respectively.
Let the monthly expenditure of Amar and Bhuvan be 3y and 2y respectively.
Savings of Bhuvan every month = 1/4(5x)
= (His income) – (His expenditure) = 5x – 2y.
=> 5x = 20x – 8y => y = 15x/8.
Ratio of savings of Amar and Bhuvan
= 6x – 3y : 1/4(5x) = 6x – 3(15x/8) : 5x/4 = 3x/8 : 5x/4
= 3 : 10. -
Question 11 of 50
11. Question
108 * 107 * 96 = ? (to the nearest hundred)
Correct
108 * 107 * 96 โก 1109400
Incorrect
108 * 107 * 96 โก 1109400
-
Question 12 of 50
12. Question
Rs.1200 divided among P, Q and R. P gets half of the total amount received by Q and R. Q gets one-third of the total amount received by P and R. Find the amount received by R?
Correct
Let the amounts to be received by P, Q and R be p, q and r.
p + q + r = 1200
p = 1/2 (q + r) => 2p = q + r
Adding ‘p’ both sides, 3p = p + q + r = 1200
=> p = Rs.400
q = 1/3 (p + r) => 3q = p + r
Adding ‘q’ both sides, 4q = p + q + r = 1200
=> q = Rs.300
r = 1200 – (p + q) => r = Rs.500.Incorrect
Let the amounts to be received by P, Q and R be p, q and r.
p + q + r = 1200
p = 1/2 (q + r) => 2p = q + r
Adding ‘p’ both sides, 3p = p + q + r = 1200
=> p = Rs.400
q = 1/3 (p + r) => 3q = p + r
Adding ‘q’ both sides, 4q = p + q + r = 1200
=> q = Rs.300
r = 1200 – (p + q) => r = Rs.500. -
Question 13 of 50
13. Question
Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.85. How much was lent at 5%?
Correct
(x*5*1)/100 + [(1500 – x)*6*1]/100 = 85
5x/100 + 90 โ 6x/100 = 85
x/100 = 5
=> x = 500Incorrect
(x*5*1)/100 + [(1500 – x)*6*1]/100 = 85
5x/100 + 90 โ 6x/100 = 85
x/100 = 5
=> x = 500 -
Question 14 of 50
14. Question
Sam purchased 20 dozens of toys at the rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. What was his percentage profit?
Correct
C.P. of 1 toy = 375/12 = Rs. 31.25
S.P of 1 toy = Rs. 33
Profit = 1.75/31.25 * 100 = 28/5 = 5.6%Incorrect
C.P. of 1 toy = 375/12 = Rs. 31.25
S.P of 1 toy = Rs. 33
Profit = 1.75/31.25 * 100 = 28/5 = 5.6% -
Question 15 of 50
15. Question
60 + 5 * 12 / (180/3) = ?
Correct
60 + 5 * 12 / (180/3) = 60 + 5 * 12 / (60)
= 60 + (5 * 12)/60 = 60 + 1 = 61.Incorrect
60 + 5 * 12 / (180/3) = 60 + 5 * 12 / (60)
= 60 + (5 * 12)/60 = 60 + 1 = 61. -
Question 16 of 50
16. Question
Find the compound interest accrued on an amount of Rs.14,800 at 13.5% p.a at the end of two years. (Round off your answer to nearest integer)
Correct
CI = 14800{ [ 1 + 13.5/100]2ย – 1 }
= 14800 { [1 + 27/200]2ย – 1
= 14800 { 2 + 27/200}{27/200}
= (74)[2 + 27/200](27) =
1998[2 + 27/200] = 3996 + 269.73 = Rs. 4266Incorrect
CI = 14800{ [ 1 + 13.5/100]2ย – 1 }
= 14800 { [1 + 27/200]2ย – 1
= 14800 { 2 + 27/200}{27/200}
= (74)[2 + 27/200](27) =
1998[2 + 27/200] = 3996 + 269.73 = Rs. 4266 -
Question 17 of 50
17. Question
A batsman in his 17thย innings makes a score of 85 and their by increasing his average by 3. What is his average after the 17thinnings?
Correct
16x + 85 = 17(x + 3)
x = 34 + 3 = 37Incorrect
16x + 85 = 17(x + 3)
x = 34 + 3 = 37 -
Question 18 of 50
18. Question
A and B can do a piece of work in 12 days and 16 days respectively. Both work for 3 days and then A goes away. Find how long will B take to complete the remaining work?
Correct
3/12 + (3 + x)/16 = 1
x = 9 daysIncorrect
3/12 + (3 + x)/16 = 1
x = 9 days -
Question 19 of 50
19. Question
What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30?
Correct
L.C.M of 12, 18, 21, 30
= 2 * 3 * 2 * 3 * 7 * 5 = 1260
Required number = 1260/2 = 630.Incorrect
L.C.M of 12, 18, 21, 30
= 2 * 3 * 2 * 3 * 7 * 5 = 1260
Required number = 1260/2 = 630. -
Question 20 of 50
20. Question
A trader marked the price of the T.V. 30% above the cost price of the T.V. and gave the purchaser 10% discount on the marked price, thereby gaining Rs.340. Find the cost price of the T.V?
Correct
Incorrect
-
Question 21 of 50
21. Question
A shopkeeper sold an article offering a discount of 5% and earned a profit of 23.5%. What would have been the percentage of profit earned if no discount was offered?
Correct
Let C.P. be Rs. 100.
Then, S.P. = Rs. 123.50
Let marked price be Rs. x. Then, 95/100 x = 123.50
x = 12350/95 = Rs. 130
Now, S.P. = Rs. 130, C.P. = Rs. 100
Profit % = 30%.Incorrect
Let C.P. be Rs. 100.
Then, S.P. = Rs. 123.50
Let marked price be Rs. x. Then, 95/100 x = 123.50
x = 12350/95 = Rs. 130
Now, S.P. = Rs. 130, C.P. = Rs. 100
Profit % = 30%. -
Question 22 of 50
22. Question
10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?
Correct
1 man’s 1 day work = 1/100
(10 men + 15 women)’s 1 day work = 1/6
15 women’s 1 day work = (1/6 – 10/100) = 1/15
1 woman’s 1 day work = 1/225
1 woman alone can complete the work in 225 days.Incorrect
1 man’s 1 day work = 1/100
(10 men + 15 women)’s 1 day work = 1/6
15 women’s 1 day work = (1/6 – 10/100) = 1/15
1 woman’s 1 day work = 1/225
1 woman alone can complete the work in 225 days. -
Question 23 of 50
23. Question
(22 * 495 + 891 * 44) / (33 * 176 + 55 * 264) = ?
Correct
(22 * 495 + 891 * 44) / (33 * 176 + 55 * 264) = (22 * 33 * 15 + 9 * 99 * 2 * 22) / (33 * 22 * 8 + 5 * 11 * 22 * 12)
= (22 * 33 * 15 + 22 * 33 * 54) / (33 * 22 * 8 + 33 * 22 * 20) = [22 * 33(15 + 54)] / [33 * 22(8 + 20)] = 69/28Incorrect
(22 * 495 + 891 * 44) / (33 * 176 + 55 * 264) = (22 * 33 * 15 + 9 * 99 * 2 * 22) / (33 * 22 * 8 + 5 * 11 * 22 * 12)
= (22 * 33 * 15 + 22 * 33 * 54) / (33 * 22 * 8 + 33 * 22 * 20) = [22 * 33(15 + 54)] / [33 * 22(8 + 20)] = 69/28 -
Question 24 of 50
24. Question
A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1500. The difference between the profit shares of A and C is?
Correct
Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit share of B is Rs. 1500
=> 5 parts out of 15 parts is Rs. 1500
Now, required difference is 6 – 4 = 2 parts
Required difference = 2/5 (1500) = Rs. 600Incorrect
Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit share of B is Rs. 1500
=> 5 parts out of 15 parts is Rs. 1500
Now, required difference is 6 – 4 = 2 parts
Required difference = 2/5 (1500) = Rs. 600 -
Question 25 of 50
25. Question
Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in.
Correct
The part of the tank filled by three pipes in one hour = 1/8
=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.
The tank can be filled in 12 hours.Incorrect
The part of the tank filled by three pipes in one hour = 1/8
=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.
The tank can be filled in 12 hours. -
Question 26 of 50
26. Question
The ratio of the radius of two circles is 1: 3, and then the ratio of their areas is?
Correct
r1: r2ย = 1: 3
ฮ r12: ฮ r22
r12: r22ย = 1: 9Incorrect
r1: r2ย = 1: 3
ฮ r12: ฮ r22
r12: r22ย = 1: 9 -
Question 27 of 50
27. Question
A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock?
Correct
Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x – 49x/50 = x/50
x/50 = 400 => x = 20000Incorrect
Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x – 49x/50 = x/50
x/50 = 400 => x = 20000 -
Question 28 of 50
28. Question
Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm.
Correct
Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them) = 1/2 (20 + 18) * (15) = 285 cm2
Incorrect
Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them) = 1/2 (20 + 18) * (15) = 285 cm2
-
Question 29 of 50
29. Question
The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is:
Correct
Let the numbers be 2x and 3x.
Then, their L.C.M = 6x. So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.Incorrect
Let the numbers be 2x and 3x.
Then, their L.C.M = 6x. So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40. -
Question 30 of 50
30. Question
(50 – ?/29)% of 4200 = 3โ196
Correct
(50 – ?/29)% of 4200 = 3โ196
Incorrect
(50 – ?/29)% of 4200 = 3โ196
-
Question 31 of 50
31. Question
An amount of Rs.1560 was divided among A, B and C in the ratio 1/2:1/3:1/4. Find the share of C?
Correct
Let the shares of A, B and C be a, b and c respectively.
a:b:c = 1/2:1/3:1/4
a:b:c = 6/12:4/12:3:12 = 6:4:3
Share of C = 3/13 * 1560 = Rs.360.Incorrect
Let the shares of A, B and C be a, b and c respectively.
a:b:c = 1/2:1/3:1/4
a:b:c = 6/12:4/12:3:12 = 6:4:3
Share of C = 3/13 * 1560 = Rs.360. -
Question 32 of 50
32. Question
A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
Correct
Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (800 + x)/60 = 65/3
x = 500 m.Incorrect
Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (800 + x)/60 = 65/3
x = 500 m. -
Question 33 of 50
33. Question
The sum of money at compound interest amounts to thrice itself in 3 years. In how many years will it be 9 times itself?
Correct
100 —- 300 — 3
900 — 3
—-
6 yearsIncorrect
100 —- 300 — 3
900 — 3
—-
6 years -
Question 34 of 50
34. Question
In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes?
Correct
Let the total number of valid votes be x.
70% of x = 70/100 * x = 7x/10
Number of votes secured by the other candidate = x – 7x/100 = 3x/10
Given, 7x/10 – 3x/10 = 172 => 4x/10 = 172
=> 4x = 1720 => x = 430.Incorrect
Let the total number of valid votes be x.
70% of x = 70/100 * x = 7x/10
Number of votes secured by the other candidate = x – 7x/100 = 3x/10
Given, 7x/10 – 3x/10 = 172 => 4x/10 = 172
=> 4x = 1720 => x = 430. -
Question 35 of 50
35. Question
There are some pigeons and hares in a zoo. If heads are counted, there are 200. If legs are counted, there are 580. The number of hares in the zoo is?
Correct
200*2 = 400
580
—–
180
1—-2
?—-180 = 90Incorrect
200*2 = 400
580
—–
180
1—-2
?—-180 = 90 -
Question 36 of 50
36. Question
In a three digit number, the hundred digit is 2 more than the tens digit and the units digit is 2 less than the tens digit. If the sum of the digits is 18, find the number?
Correct
Let the three digit numbers be 100a + 10b + c
a = b + 2
c = b – 2
a + b + c = 3b = 18 => b = 6
So a = 8 and b = 4
Hence the three digit number is: 864Incorrect
Let the three digit numbers be 100a + 10b + c
a = b + 2
c = b – 2
a + b + c = 3b = 18 => b = 6
So a = 8 and b = 4
Hence the three digit number is: 864 -
Question 37 of 50
37. Question
Simple interest on a sum at 4% per annum for 2 years is Rs.80. The C.I. on the same sum for the same period is?
Correct
SI = 40 + 40
CI = 40 + 40 + 1.6 = 81.6Incorrect
SI = 40 + 40
CI = 40 + 40 + 1.6 = 81.6 -
Question 38 of 50
38. Question
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are picked at random, what is the probability that they are all blue?
Correct
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue = ยณCโ/ยนโตCโ = (1 * 3 * 2 * 1)/(15 * 14 * 13) = 1/455Incorrect
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue = ยณCโ/ยนโตCโ = (1 * 3 * 2 * 1)/(15 * 14 * 13) = 1/455 -
Question 39 of 50
39. Question
A, B and C can do a piece of work in 7 days, 14 days and 28 days respectively. How long will they taken, if all the three work together?
Correct
1/7 + 1/14 + 1/28 = 7/28 = 1/4 => 4 days
Incorrect
1/7 + 1/14 + 1/28 = 7/28 = 1/4 => 4 days
-
Question 40 of 50
40. Question
Three years ago the average age of a family of six members was 19 years. A boy have been born, the average age of the family is the same today. What is the age of the boy?
Correct
6 * 22 = 132
7 * 19 = 133
————–
1Incorrect
6 * 22 = 132
7 * 19 = 133
————–
1 -
Question 41 of 50
41. Question
A man can swim in still water at 4.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
Correct
M = 4.5
S = x
DS = 4.5 + x
US = 4.5 + x
4.5 + x = (4.5 – x)2
4.5 + x = 9 -2x
3x = 4.5
x = 1.5Incorrect
M = 4.5
S = x
DS = 4.5 + x
US = 4.5 + x
4.5 + x = (4.5 – x)2
4.5 + x = 9 -2x
3x = 4.5
x = 1.5 -
Question 42 of 50
42. Question
The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is?
Correct
LCM = 1400
1400 – 6 = 1394Incorrect
LCM = 1400
1400 – 6 = 1394 -
Question 43 of 50
43. Question
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Correct
Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.
Incorrect
Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.
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Question 44 of 50
44. Question
Find the one which does not belong to that group ?
Correct
All are blood relation except Daughter-in-law.
Incorrect
All are blood relation except Daughter-in-law.
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Question 45 of 50
45. Question
With a uniform speed a car covers the distance in 8 hours. Had the speed been increased by 4 km/hr, the same distance could have been covered in 7 1/2 hours. What is the distance covered?
Correct
Let the distance be x km. Then,
x/(7 1/2) – x/8 = 4
2x/15 – x/8 = 4 => x = 480 km.Incorrect
Let the distance be x km. Then,
x/(7 1/2) – x/8 = 4
2x/15 – x/8 = 4 => x = 480 km. -
Question 46 of 50
46. Question
? % of 400 + 40% of 160 = 17% of 400
Correct
? % of 400 + 40% of 160 = 17% of 400
?/100 of 400 + 40/100 of 160 = 17/100 of 400
?(4) + 64 = 68 => ? = 1Incorrect
? % of 400 + 40% of 160 = 17% of 400
?/100 of 400 + 40/100 of 160 = 17/100 of 400
?(4) + 64 = 68 => ? = 1 -
Question 47 of 50
47. Question
Two pipes can separately fill a tank in 20 and 30 hours respectively. Both the pipes are opened to fill the tank but when the tank is full, a leak develops in the tank through which one-third of water supplied by both the pipes goes out. What is the total time taken to fill the tank?
Correct
1/20 + 1/30 = 1/12
1 + 1/3 = 4/3
1 — 12
4/3 — ?
4/3 * 12 = 16 hrsIncorrect
1/20 + 1/30 = 1/12
1 + 1/3 = 4/3
1 — 12
4/3 — ?
4/3 * 12 = 16 hrs -
Question 48 of 50
48. Question
In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case?
Correct
Assume X soldiers join the fort. 1200 soldiers have provision for 1200(days for which provisions last them)(rate of consumption of each soldier)
= 1200(30)(3) kg
Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) kg
As the same provisions are available
=> 1200(30)(3) = (1200 + x)(25)(2.5)
x = [1200(30)(3)]/[(25)(2.5)] – 1200
x = 528Incorrect
Assume X soldiers join the fort. 1200 soldiers have provision for 1200(days for which provisions last them)(rate of consumption of each soldier)
= 1200(30)(3) kg
Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) kg
As the same provisions are available
=> 1200(30)(3) = (1200 + x)(25)(2.5)
x = [1200(30)(3)]/[(25)(2.5)] – 1200
x = 528 -
Question 49 of 50
49. Question
Two trains of length 120 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?
Correct
Relative speed = (42 + 30) * 5/18 = 4 * 5 = 20 mps.
Distance covered in passing each other = 120 + 280 = 400 m.
The time required = d/s = 400/20 = 20 sec.Incorrect
Relative speed = (42 + 30) * 5/18 = 4 * 5 = 20 mps.
Distance covered in passing each other = 120 + 280 = 400 m.
The time required = d/s = 400/20 = 20 sec. -
Question 50 of 50
50. Question
A candidate got 35% of the votes polled and he lost to his rival by 2250 votes. How many votes were cast?
Correct
35%———–L
65%———–W
——————
30%———-2250
100%———? => 7500Incorrect
35%———–L
65%———–W
——————
30%———-2250
100%———? => 7500