RBI Assistant Mains Test Series, RBI Assistant Mains Online Test Series

1 man’s 1 day work = 1/48; 1 woman’s 1 day work = 1/60.
6 men’s 2 day’s work = 6/48 * 2 = 1/4.
Remaining work = (1 – 1/4) = 3/4
Now, 1/60 work is done in 1 day by 1 woman.
So, 3/4 work will be done in 3 days by (60 * 3/4 * 1/3) = 15 women.

C.P. of 6 toffees = Re. 1
S.P. of 6 toffees = 120% of Re. 1 = Rs. 6/5
For Rs. 6/5, toffees sold = 6. For re. 1.
Toffees sold = 6 * 5/6 = 5

Given, 40% of Ram’s marks = 20% of Rahim’s marks = 30% of Robert’s marks.
Given, marks of Robert = 80
30% of 80 = 30/100 * 8 = 24
Given, 40% of Ram’s marks = 24.
=> Ram’s marks = (24 * 100)/40 = 60
Also, 20% of Rahim’s marks = 24
=> Rahim’s marks = (24 * 100)/20 = 120
Average marks of Ram and Rahim = (60 + 120)/2 = 90.

Area of an equilateral triangle = √3/4 S²
If S = 16, Area of triangle = √3/4 * 16 * 16 = 64√3 cm²;

3000 – 3 = 2997

Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (5050 * 2) = 10100 — (i)
Q + R = (6250 * 2) = 12500 — (ii)
P + R = (5200 * 2) = 10400 — (iii)
Adding (i), (ii) and (iii), we get:
2(P + Q + R) = 33000 = P + Q + R = 16500 — (iv)
Subtracting (ii) from (iv), we get, P = 4000.
P’s monthly income = Rs. 4000.

Let x = 5k and y = 2k.
Then, (8x + 9y)/(8x + 2y)
= [(8 * 5k) + (9 * 2k)] / [(8 * 5k) + (2 * 2k)] = 58k/44k = 29/22
(8x + 9y):(8x + 2y) = 29:22

3: 4
A = 3/7*210 = 90
390: 400
39:40

Simple interest = (18000 * 4 * 15)/100 = Rs. 10800
Amount = P + I = 18000 + 10800 = Rs. 28800

10 * 150 = 1500
3 * 100 + 5 * 150 = 1050
1500 – 1050 = 450

15/25 + 10/x = 1 => x = 25
1/25 + 1/25 = 2/25
25/2 = 12 1/2 days

Let the principal be Rs.P
S.I at 5% p.a in 8 years on Rs.P = Rs.500
(P)(8)(5)/100 = 500
P = 1250
C.I on Rs.2P i.e., Rs.2500 at 5% p.a in two years
=2500{ [1 + 5/100]² – 1} = 2500{ 21² – 20² /20²}
= 2500/400(441 – 400)
= 25/4(41) = 1025/4 = Rs.256.25

32/100 * 425 – x/100 * 250 = 36
=> x/100 * 250 = 136 – 36 = 100
=> x = (100 * 100)/250 = 40

Let the amount with R be Rs.r
r = 2/3 (total amount with P and Q)
r = 2/3(6000 – r) => 3r = 12000 – 2r
=> 5r = 12000 => r = 2400.

Let x percent of 80 be 64.
80 * x/100 = 64 => x = (64 * 100)/80 => x = 80.
80% of 80 is 64.

They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
6000 : 8000 => 3:4

4 * 27 * 3125 = 2² * 3³ * 5⁵;
8 * 9 * 25 * 7 = 2³ * 3² * 5² * 7;
16 * 81 * 5 * 11 * 49 = 2⁴ * 3⁴ * 5 * 7² * 11
H.C.F = 2² * 3² * 5 = 180.

20                 15           5
25                  20           8
500 + 300 + 40 = 840/40 = 21

Let C.P. be Rs. x.
Then, 5% of x = 350 – 340 = 10
x/20 = 10 => x = 200

P(1 + 20/100)ⁿ > 2P or (6/5)ⁿ > 2
Now, (6/5 * 6/5 * 6/5 * 6/5) > 2. So, n = 4 years.

Excluded number = (27 * 5) – (25 * 4) = 135 – 100 = 35.

Total score of the batsman in 20 matches = 800.
Total score of the batsman in the next 10 matches = 130.
Total score of the batsman in the 30 matches = 930.
Average score of the batsman = 930/30 = 31.

5358 * 51 = 5358 * (50 + 1)
= 5358 * 50 + 5358 * 1
= 267900 + 5358 = 273258

Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 9 = 150 meter

Let A’s speed = x km/hr. Then, B’s speed = (7 – x) km/ hr.
So, 24/x + 24/(7 – x) = 14
x² – 98x + 168 = 0
(x – 3)(x – 4) = 0 => x = 3 or 4.
Since, A is faster than B, so A’s speed = 4 km/hr and B’s speed = 3 km/hr.

T = 9/45 * 60 = 12

Let the ten’s and unit’s digit be x and 8/x respectively.
Then,
(10x + 8/x) + 18 = 10 * 8/x + x
9x² + 18x – 72 = 0
x² + 2x – 8 = 0
(x + 4)(x – 2) = 0
x = 2
So, ten’s digit = 2 and unit’s digit = 4.
Hence, required number = 24.

15 CP = 18 SP
18 — 3 CP loss
100 — ? => 16 2/3% loss

504/M = 384/800
(504 * 800) / 384 = M
M = 1050

130
14
——-
361—— 144
100%——? => 400

2 * 22/7 * 14 = 88
88 * 1 1/2 = Rs.132

The number of ways to select three men and two women such that one man and one woman are always selected = Number of ways selecting two men and one woman from men and five women
= ⁴C₂ * ⁵C₁ = (4 * 3)/(2 * 1) * 5
= 30 ways.

Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) = 90 years.
Sum of the present age of wife and child = (20 * 2 + 5 * 2) = 50 years.
Husband’s present age = (90 – 50) = 40 years.

Let the number be a
Given, 15/100 * 30/100 * 50/100 * a = 90
=> 3/20 * 3/10 * 1/2 * a = 90
=> a = 10 * 20 * 10 * 2 = 4000.

x Not younger_______ ↑
The last ball can be thrown by any of the remaining 6 players. The first 6 players can throw the ball in ⁶P₆ ways.
The required number of ways = 6(6!) = 4320

X * (110/100) * (95/100) = 1045
X * (11/10) * (1/100) = 11
X = 1000

Required fraction = L.C.M of 6/7, 5/14, 10/21
= (L.C.M of 6, 5, 10) / (H.C.F of 7, 14, 21) = 30/7

Given Exp. = – 84 * (30 – 1) + 365
= – (84 * 30) + 84 + 365
= – 2520 + 449 = – 2071

C.P. of 1 kg = 420/7 = Rs. 6
S.P. of 1 kg = Rs. 6.50
Gain % = 0.50/6 * 100 = 25/3 = 8 1/3 %

The distance to be covered = Sum of their lengths = 200 + 300 = 500 m.
Relative speed = 72 -36 = 36 kmph = 36 * 5/18 = 10 mps.
Time required = d/s = 500/10 = 50 sec.

Let the parts be x, y and [2600 – (x + y)].
Then,
(x * 4 * 1)/100 = (y * 6 * 1)/100 = {[2600 – (x + y)] * 8 * 1}/100
y/x = 4/6 = 2/3 or y = 2/3 x
So, (x * 4 * 1)/100 = [(2600 – 5/3 x) * 80/100
52x = (7800 * 8) => x = 1200
Money invested at 4% = Rs. 1200.

Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.
Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total
They would take 9/2 days = 4 (1/2) days to complete the work working together.

(27²/4^-3)^-5/6 = [(3³)²/(2²)^-3]^-5/6
= (3⁶ * 2⁶)^{-5/6
= (66})^-5/6 = 1/6⁵ = 1/ 7776.

Let the cost price of an article be Rs. x.
(19% of x) – (12% of x) = 105
19x/100 – 12x/100 = 105 => 7x = 105 * 100
=> x = 1500
Cost price = Rs. 1500

Let the radii of the smaller and the larger circles be s m and l m respectively.
2∏s = 264 and 2∏l = 352
s = 264/2∏ and l = 352/2∏
Difference between the areas = ∏l² – ∏s²
= ∏{176²/∏² – 132²/∏²}
= 176²/∏ – 132²/∏
= (176 – 132)(176 + 132)/∏
= (44)(308)/(22/7) = (2)(308)(7) = 4312 sq m

B = 1/8 – 1/2 = 1/24 => 24 days

The circumference of the circle is equal to the permeter of the rectangle.
Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5
=>  x = 1
Therefore l = 6 cm and b = 5 cm Area of the rectangle = 6 * 5 = 30 cm²